X^2-11200x+160=0

Solution for X^2-11200x+160=0 equation:

X^2-11200X+160=0

a = 1; b = -11200; c = +160;
Δ = b2-4ac
Δ = -112002-4·1·160
Δ = 125439360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{125439360}=\sqrt{64*1959990}=\sqrt{64}*\sqrt{1959990}=8\sqrt{1959990}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11200)-8\sqrt{1959990}}{2*1}=\frac{11200-8\sqrt{1959990}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11200)+8\sqrt{1959990}}{2*1}=\frac{11200+8\sqrt{1959990}}{2}
$